Digonal number pattern in bash solved

  printf "Enter row number";
    read n;
    c=1
    for((i=1;i<=(n-1);i++))
    {
   
        for((j=1;j<=(n-1);j++))
        {
            if(((i==j)||(j==(n-i))))
            then
            printf $c ;
            else
            printf " ";
            fi
        }
        if ((c>=4))
        then
        ((c=c-1));
        else
        ((c=c+1));
        fi
        printf "\n";
    }

 

 

If statement compound condition matching

#!/bin/ksh
#prompt the user to enter a number
print -n "Enter your age: "
read age
print
print -n "enter the number of children you have :"
read numberofchildren
if ( (( age < 30 )) && (( numberofchildren==0 )) ); then #the space after the ( and before the ) is important

print "Single and loving it"
fi
if (  ((age > 30)) || ((numberofchildren!=0)) ); then
print "things could be worse"
fi
#operators are &&,||